A streamlined and almost symmetrical car of mass M has center of gravity at a distance p from the rear wheel, q from the front wheel and h from the road. If the car has required power and friction, the maximum acceleration developed without tipping over towards back is
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For equilibrium
Ma max × h = Mg × p
(q will not matter as per statement of the question because when the car is about to topple, the whole reaction is on the rear wheel as front wheel is no more in contact with the ground and here R is the reaction of the rear wheel)
a max = 
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